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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020

PhysicsEasysingle choice

A proton when accelerated through a potential difference of $V$ volt has a wavelength $λ$ associated with it. An $α -$ particle in order to have the same $λ$ must be accelerated through potential difference of

Options:

Answer:

Solution:

$λ_{P} = λ_{α}$

$or \frac{h}{\sqrt{2 m_{p} Q_{P} V_{p}}} = \frac{h}{\sqrt{2 m_{α} Q_{α} V_{α}}}$

$∴ m_{p} Q_{p} V_{p} = m_{α} Q_{α} V_{α}$

$∴ V_{α} = (\frac{m_{p}}{m_{α}}) (\frac{Q_{p}}{Q_{α}}) V = (\frac{1}{4}) (\frac{1}{2}) V = \frac{V}{8}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

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