Physics - Modern Physics Question with Solution | TestHub

According to Moseley's law $\sqrt{\mathrm{v}}=\mathrm{a}(\mathrm{z}-\mathrm{b})$ or $\mathrm{v}={\mathrm{a}}^2(\mathrm{z}-\mathrm{b}{)}^2$ or $\frac{\mathrm{c}}{\lambda }={\mathrm{a}}^2(\mathrm{z}-\mathrm{b}{)}^2$ $\therefore \frac{{\lambda }_1}{{\lambda }_2}=\frac{{\left({\mathrm{z}}_2-1\right)}^2}{{\left({\mathrm{z}}_1-1\right)}^2}$ Here ${\lambda }_1=\lambda ,{\lambda }_2=4\lambda ,{\mathrm{z}}_1=11$ and ${\mathrm{z}}_2=$ ? $\therefore \frac{1}{4\lambda }=\frac{{\left(z_2-1\right)}^2}{(11-1{)}^2}$ or ${\left({\mathrm{z}}_2-1\right)}^2=25$ or ${\mathrm{z}}_2=6$