Physics - Modern Physics Question with Solution | TestHub

The momentum of striking electrons,

$\text{p}=\frac{\text{h}}{\lambda }$

Therefore the kinetic energy of striking electrons,

$\text{K}=\frac{{\text{p}}^2}{2\text{m}}=\frac{{\text{h}}^2}{2\text{m}{\lambda }^2}$

This is also the maximum energy of$\mathrm{X}$-ray photons.

Therefore,$\frac{\text{hc}}{{\mathrm{\lambda }}_0}=\frac{{\text{h}}^2}{2\text{m}{\mathrm{\lambda }}^2}$or${\mathrm{\lambda }}_0=\frac{2\text{m}{\mathrm{\lambda }}^2\text{c}}{\text{h}}$