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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2019

PhysicsMediumsingle choice

$15 eV$ is given to $e^{-}$ in $4^{th}$ orbit, then find its final energy when it comes out of $H$ -atom.

Options:

Answer:

Solution:

Energy of $4^{th}$ orbit of $H$ -atom $= - 13.6 \times \frac{1}{16} = - 0.85 eV$ So energy released $=$ total energy - ionization energy of $4^{th}$ orbit $= 15 - 0.85 = 14.15 eV$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2019

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