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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

PhysicsEasysingle choice

A radioactive sample $S_{1}$ having the activity $A_{1}$ has twice the number of nuclei as another sample $S_{2}$ of activity $A_{2}$ . If $A_{2} = 2 A_{1},$ then the ratio of half-life of $S_{1}$ to the half-life of $S_{2}$ is

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Answer:

Solution:

Activity, $A = λ N = \frac{0.693}{T_{1 / 2}} N$

Where T_1/2is the half-life of a radioactive sample,

$∴ \frac{A_{1}}{A_{2}} = \frac{N_{1}}{T_{1}} \times \frac{T_{2}}{N_{2}}$

$\frac{T_{1}}{T_{2}} = \frac{A_{2}}{A_{1}} \times \frac{N_{1}}{N_{2}}$

$= \frac{{2 A}_{1}}{A_{1}} \times \frac{{2 N}_{2}}{N_{2}} = \frac{4}{1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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