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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2020

PhysicsMediumstatement

An electron of mass $m$ and magnitude of charge $e$ at rest, gets accelerated by a constant electric field $E$ . The rate of change of de-Broglie wavelength of this electron at a time $t$ is (ignore relativistic effects)

Options:

Answer:

Solution:

The acceleration of the electron is

$a = \frac{e E}{m}$

The velocity of the electron as a function of time is

$v = a t = \frac{e E}{m} t$

The de-Broglie wavelength is

$λ = \frac{h}{m v}$

$λ = \frac{h}{m (\frac{e E}{m}) t}$

$λ = \frac{h}{e E t}$
$\frac{d λ}{d t} = - \frac{h}{e E t^{2}}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

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