Physics - Modern Physics Question with Solution | TestHub

$mV=m{V}_A+\frac{m}{2}{V}_B$

$V=V_A+\frac{V_B}{2}------------\text{(i)}$

$V=V_B-V_A------------\text{(ii)}$

$\text{Solving (i) and (ii)}$

$2V=\frac{3V_B}{2}$

$\therefore V_B=\frac{4V}{3}$

$V_A=V_B-V=\frac{V}{3}$

$P_A=\frac{mV}{3}$

$P_B=\frac{m}{2}.\frac{4V}{3}$

$\frac{{\lambda }_A}{{\lambda }_B}=\frac{h\times P_B}{P_A\times h}=\frac{\frac{2mV}{3}}{\frac{mV}{3}}=2$