The work function of a metal is 1 eV . Light of wavelength 3000 A ∘ is incident on this metal surface. The velocity of emitted photoelectrons will be

1 2 m v 2 = h c λ - ϕ 0 = 6.63 × 10 - 34 × 3 × 10 8 ( 3 × 10 - 7 ) × 1.6 × 10 - 19 - 1 = 4.14 - 1 = 3.14 e V or v = 2 × 3.14 × 1.6 × 10 - 19 9.1 × 10 - 31 = 10 6 m s - 1

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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

The work function of a metal is $1 eV$ . Light of wavelength $3000 \overset{\circ}{A}$ is incident on this metal surface. The velocity of emitted photoelectrons will be

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Answer:

Solution:

$\frac{1}{2} m v^{2} = \frac{h c}{λ} - ϕ_{0}$

$= \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{(3 \times 10^{- 7}) \times 1.6 \times 10^{- 19}} - 1$

$= 4.14 - 1 = 3.14 e V$

or $v = \sqrt{\frac{2 \times 3.14 \times 1.6 \times 10^{- 19}}{9.1 \times 10^{- 31}}} = 10^{6} m s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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