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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

PhysicsEasysingle choice

The activity of a radioactive sample is measured as $9750$ counts per minute at $t = 0$ and as $975$ counts per minute at $t = 5$ minutes. The decay constant is approximately

Options:

Answer:

Solution:

$\frac{d N}{d t} = λ N$

$9750 = λ N_{0}$ …. (i)

$975 = λ N$ … (ii)

Dividing (i) by (ii)

$\frac{N}{N_{0}} = \frac{1}{10}$

$λ = \frac{2.303}{t} \log \frac{N_{0}}{N} = \frac{2.303}{5} \log 10$

$= 0.4606 = 0.461$ per minute

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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