Physics - Magnetism Question with Solution | TestHub

$$I_1=30\mathrm{A}I=10\mathrm{A}{I}_2=20\mathrm{A}$$
Also given; length of wire $Q$ $=25\mathrm{cm}=0.25\mathrm{m}$ Force on wire $\mathrm{Q}$ due to wire $\mathrm{R}$ $$\begin{array}{rl}& F_{QR}=10^{-7}\times \frac{2\times 20\times 10}{0.05}\times 0.25\\ & =20\times 10^{-5}\mathrm{N}\text{ (Towards left) }\end{array}$$ Force on wire $\mathrm{Q}$ due to wire $\mathrm{P}$ $$\begin{array}{rl}& F_{QP}=10^{-7}\times \frac{2\times 30\times 10}{0.03}\times 0.25\\ & =50\times 10^{-5}\mathrm{N}\text{ (Towards right) }\\ & \text{ Hence, }{F}_{\text{net }}=F_{QP}-F_{QR}\\ & =50\times 10^{-5}\mathrm{N}-20\times 10^{-5}\mathrm{N}\\ & =3\times 10^{-4}\mathrm{N}\text{ towards right }\end{array}$$