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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldMedium2 minQB

PhysicsMediumsingle choice

A beam of protons with speed $4 \times 10^{5} m s^{- 1}$ enters a uniform magnetic field of $0.3 T$ at an angle $60 °$ to the magnetic field, the pitch of the resulting helical path of protons is close to : (Mass of the proton $= 1.67 \times 10^{- 27} kg$ , charge of the proton $= 1.69 \times 10^{- 19} C$ )

Options:

Answer:

Solution:

Pitch

$= (Vcos θ) T$

$= (Vcos θ) \frac{2 π m}{eB}$

$= (4 \times 10^{5} \cos 60 °) \frac{2 π}{0.3 \times 10} (\frac{1.67 \times 10^{- 27}}{1.69 \times 10^{19}})$

$4 cm$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: QB

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