Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minQB
PhysicsMediumsingle choice

A very long wire ABDMNDC is shown in figure carrying current I. AB and BC parts are straight, long and at right angle. At D wire forms a circular turn DMND of radius R. AB, BC parts are tangential to circular turn at N and D. Magnetic filed at the center of circle is:

Options:

Answer:
A
Solution:


B0→=B0→1+B0→2+B0→3+B0→4
μ0i4πRsin⁡90°-sin45°⨂+μ0i2R⨀+μ0i4πR(sin45°+sin90°)⨀
-μ0i4πR1-12+μ0i2R+μ0i4πR12+1⨀
=μ0i4πR-1+12+2π+12+1⨀=μ0i4πR2+2π⨀=μ0i2πR12+π⨀

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law
⏱ 2mℹ️ Source: QB

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