A long wire carries a steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is B . It is then bent into a circular loop of n turns. The magnetic field a

Question

A long wire carries a steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is $B$ . It is then bent into a circular loop of $n$ turns. The magnetic field at the centre of the coil will be

Options:

Answer:

B

Solution:

$B^{'} = \frac{π μ _{0} I}{2 r ^{'}} = n^{2} \frac{μ _{0} ππ}{ℓ} = n^{2} B$ .

TestHub · Accepted Answer

B ′ = 2 r ′ π μ 0 ​ I ​ = n 2 ℓ μ 0 ​ ππ ​ = n 2 B .

Physics - Magnetism Question with Solution | TestHub

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