Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsMiscellaneousHard2 minQB

PhysicsHardsingle choice

Passage / Comprehension

When baseball players throw the ball in from the out-field they usually allow it to take one bounce before it reaches the in field, on theory that the ball arrives sooner that way. Suppose the angle at which a bounced ball leaves the ground is same as the angle at which the outfielder throw it as shown in figure.

Ball speed after the bounce is one-half of what it was before bounce. Assume that ball is always thrown with same initially speed.

At what angle $θ$ should the fielder throw the ball to make it go the same distance D with one bounce as a ball thrown upward at 45° with no bounce.

Options:

Answer:

Solution:

$D = \frac{u ^{2}}{g} = \frac{u ^{2} s i n 2 θ}{g} + \frac{( \frac{u}{2} ) ^{2} s i n 2 θ}{g}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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