If T be the total time of flight of a current of water and H be the maximum height attained by it from the point of projection, then H / T will be − ( u = projection velocity, θ = projection angle)

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TestHub · Accepted Answer

To find H/T, we use the formulas for maximum height $H = \frac{u ^{2} s i n ^{2} θ}{2 g}$ and total time of flight $T = \frac{2 u s i n θ}{g}$ .

$\frac{H}{T} = \frac{\frac{u ^{2} s i n ^{2} θ}{2 g}}{\frac{2 u s i n θ}{g}} = \frac{u ^{2} sin ^{2} θ}{2 g} \times \frac{g}{2 u sin θ} = \frac{u sin θ}{4}$

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