Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DEasy2 minPYQ_2020

PhysicsEasysingle choice

The coordinates of a moving particle at any time $t$ are given by $x = α t^{3}$ and $y = β t^{3}$ . The speed of the particle at time $t$ is given by

Options:

Answer:

Solution:

$∵ x = α t^{3}$

$∴ \frac{d x}{d t} = 3 α t^{2} \Rightarrow v_{x} = 3 α t^{2}$

Again $y = β t^{3}$

$∴ \frac{d y}{d t} \Rightarrow v_{y} = 3 β t^{2}$

Since, $v^{2} = v_{x}^{2} + v_{y}^{2}$

$v^{2} = (3 α t^{2})^{2} + (3 β t^{2})^{2} = (3 t^{2})^{2} (α^{2} + β^{2})$

Or $v = 3 t^{2} \sqrt{α^{2} + β^{2}}$

Subject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2020

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