Physics - Kinematics Question with Solution | TestHub

The position of a projectile launched from the origin at $t=0$ is given by $\vec{r}=(40\hat{i}+50\hat{j})\mathrm{m}$ at $t=$ $2\mathrm{s}$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is $($ take $g=10{\mathrm{ms}}^{-2})$\