Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

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Passage / Comprehension

A balloon rises up with constant acceleration of 10 m/s² from the Earth's surface at t=0.

After 4 seconds, a particle drops from the balloon.

Total air time of particle is :-

Options:

Answer:

Solution:

By using $s = ut + \frac{1}{2} at^{2}$ For particle : $- 80 = 40 t + \frac{1}{2} (- 10) t^{2}$ $\Rightarrow 5 t^{2} - 40 t - 80 = 0$ $\Rightarrow t^{2} - 8 t - 16 = 0$ $\Rightarrow t = \frac{8 \pm 64 + 64}{2}$ $\Rightarrow t = 4 \pm 42$ as t can't be negative so $t = (4 + 42) s$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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