Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DEasy2 minPYQ_2020

PhysicsEasysingle choice

A point moves in the $x - y$ plane according to $x = A \sin ω t$ and $y = A (1 - cos ω t)$ where $A$ and $ω$ are positive constants. The distance traversed by the point during the time $τ$ is

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Answer:

Solution:

Distance travelled by point in time t is:
$S = \int_{0}^{τ} |\vec{V}| d t$
$∵ |\vec{V}| = \sqrt{{V_{x}}^{2} + {V_{y}}^{2}}$
Where, $V_{x} = \frac{d x}{d t} = A ω \cos ω t and$ $V_{y} = \frac{d y}{d t} = A ω \sin ω t$
$S = \int_{0}^{τ} A ω d t = A ω τ$

Stream:NTA_ABHYASSubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2020

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