Region I and II are separated by a spherical surface of radius 25 cm . An object is kept in region I at a distance of 40 cm from the surface. The distance of the image from the surface is:

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μ 2 v - μ 1 u = μ 2 - μ 1 R 1 . 4 v - 1 . 25 - 40 = 1 . 4 - 1 . 25 - 25 1 . 4 v = - 0 . 15 25 - 1 . 25 40 v = - 37 . 58 cm Hence option ( 4 ) .

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