Two plane mirrors M 1 and M 2 are at right angle to each other shown. A point source P is placed at a and 2 a meter away from M 1 and M 2 respectively. The shortest distance between the images thus fo

Question

Two plane mirrors M 1 and M 2 are at right angle to each other shown. A point source P is placed at a and 2 a meter away from M 1 and M 2 respectively. The shortest distance between the images thus formed is : (Take 5 = 2 . 3 )

TestHub · Accepted Answer

We know that the formula of the distance between two points is, $d = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$ , now put the values from the above the diagram in the above formula, then the distance between $I_{1}$ and $I_{2}, d = \sqrt{(4 a)^{2} + (2 a)^{2}} \approx 4.6 a$

Physics - Geometrical Optics Question with Solution | TestHub

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