The magnetic field within a long, straight solenoid with a circular cross-section of radius $r$ is (as shown) increasing at a rate of $α$ .

The rate of change of flux through a circle with radius $a$ inside the solenoid, normal to the axis of the solenoid and with centre on the solenoid axis is

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Answer:

C

Solution:

Rate of change of flux through circle with radius $a$

$\frac{{dϕ}_{m}}{dt} = A \frac{dB}{dt} = {πa}^{2} α$

TestHub · Accepted Answer

Rate of change of flux through circle with radius a dϕ m dt = A dB dt = πa 2 α

Physics - EMI/AC Question with Solution | TestHub

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