Value of V C 4 V L is :-

V R 2 + V L 2 = 15 0 2 , so V L = 90 V ; V C = 90 − 50 = 40 V V C 4 V L = 40 4 × 90 = 9 Answer 9.00

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PhysicsEMI/AC271Medium2 minQB

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Passage / Comprehension

In the RLC series circuit shown, the readings of voltmeters are $V_{1} = 150 V, V_{2} = 50 V$ and the source has emf 130 V .\\

Value of $\frac{4 V _{L}}{V _{C}}$ is :-

Answer:

9.00

Solution:

$V_{R}^{2} + V_{L}^{2} = 15 0^{2}$ , so $V_{L} = 90 V$ ; $V_{C} = 90 - 50 = 40 V$

$\frac{4 V _{L}}{V _{C}} = \frac{4 \times 90}{40} = 9$

Answer 9.00

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:271

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