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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsMedium2 minQB

PhysicsMediumnumerical

The frequencies at which the current amplitude in an LCR series circuit becomes $\frac{1}{2}$ times its maximum value, are $212 r a d s^{- 1}$ and $232 r a d s^{- 1}$ . The value of resistance in the circuit is $R = 5Ω$ . The self inductance in the circuit is _____ $m H$ .

Answer:

250.00

Solution:

Bandwidth of RLC circuit is $B W = f_{2} - f_{1}$ $= \frac{R}{2 π L}$
Or, $B W = ω_{2} - ω_{1} = \frac{R}{L}$
$B W = 232 - 212 = \frac{R}{L}$
Thus, self inductance in the circuit is $L = \frac{5}{20} = 250 mH$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

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