A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW . Assuming the transformer to be ideal with purely resistive load and working on unity power factor,

Question

A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW . Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

TestHub · Accepted Answer

Since the transformer is assumed to be purely resistive, the power of the transformer can be calculated with $P = \frac{V ^{2}}{R}$ . Therefore,
For the primary coil,
$P = \frac{( 8 \times 1 0 ^{3} ) ^{2}}{R _{P}} = 80 \times 1 0^{3} W$
$\Rightarrow R_{P} = 800Ω$
For the secondary coil,
$P = \frac{( 160 ) ^{2}}{R _{S}} = 80 \times 1 0^{3} W$
$\Rightarrow R_{S} = 0.32Ω$

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