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PhysicsElasticityMiscellaneousMedium2 minQB

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Extension-stress graph for a wire initially $1 m$ long is shown. Its Young's modulus is:

Answer:

Solution:

Slope $= \frac{( 4 - 2 ) 1 0 ^{- 3}}{( 8000 - 4000 ) 1 0 ^{3}} = 5 \times 1 0^{- 10} m/Pa$ .

$Y = \frac{L}{slope} = 2 \times 1 0^{9} Pa$ .

The plotted coordinates give the same secant ratio and incremental slope.

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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