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PhysicsElasticityMiscellaneousMedium2 minQB

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A uniform rod ( $m, ℓ, A, y$ ) rotates with angular speed $ω$ about a perpendicular axis through one end. Ignore gravity. Midpoint strain is:

Answer:

Solution:

Outer-half mass is $\frac{m}{2}$ .

Centre radius is $\frac{3 ℓ}{4}$ .

$T = (\frac{m}{2}) ω^{2} (\frac{3 ℓ}{4}) = \frac{3 m ω ^{2} ℓ}{8}$ .

$ϵ = \frac{T}{A y} = \frac{3 m ω ^{2} ℓ}{8 A y}$ .

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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