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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minPYQ_2024

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The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young's modulus, respectively, are $8 \times 1 0^{8} N m^{- 2}$ and $2 \times 1 0^{11} N m^{- 2}$ , is:NEET 2024

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Solution:

In the case for maximum elongation, Stress $=$ Elastic limit $δ_{m a x} = \frac{σ _{elastic} \times L}{Young’s modulus} = \frac{8 \times 1 0 ^{8} \times 1}{2 \times 1 0 ^{11}} = 4 \times 1 0^{- 3} = 4 mm$ i.e. maximum elongation is 4 mm

Stream:NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2024

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