Physics - Elasticity Question with Solution | TestHub

Solution:

To melt 1 kg of ice at $0^{\circ }\mathrm{C}$ requires $Q_{melt}=m{L}_f=(1kg)(3.34\times 10^{5}J/kg)=3.34\times 10^{5}J$.

The heat released by 1 kg of water cooling from $10^{\circ }\mathrm{C}$ to $0^{\circ }\mathrm{C}$ is $Q_{water}=mc\Delta T=(1kg)(4186J/k{g}^{\circ }C)(10^{\circ }C)=4.186\times 10^{4}J$.

Since $Q_{water}<Q_{melt}$, not all the ice will melt. The final temperature will remain $0^{\circ }\mathrm{C}$.