The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 %$ is _____ $m$ .
(Take density of sea water $= 10^{3} kg m^{- 3}$ , Bulk modulus of rubber $= 9 \times 10^{8} N m^{- 2}$ , and $g = 10 m s^{- 2}$ )

Question

The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 %$ is _____ $m$ .

(Take density of sea water $= 10^{3} kg m^{- 3}$ , Bulk modulus of rubber $= 9 \times 10^{8} N m^{- 2}$ , and $g = 10 m s^{- 2}$ )

TestHub · Accepted Answer

Bulk modulus is given by, B = - ∆ P ∆ V V ⇒ ∆ P = - B ∆ V V ⇒ ρ g h = - B ∆ V V ⇒ 10 3 × 10 × h = - 9 × 10 8 × - 0 . 02 100 ⇒ h = 18 m

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