The elastic limit of brass is 379 M P a . The minimum diameter of a brass rod if it is to support a 400 N load without exceeding its elastic limit will be

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Stress = F A Elastic limit is 379 M P a ⇒ 379 × 10 6 = 400 A = 400 π d 2 / 4 d = 400 × 4 π × 379 × 10 6 = 1.16 × 10 - 3 m = 1.16 m m

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