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PhysicsElasticityMiscellaneousEasy2 minPYQ_2023
PhysicsEasysingle choice

An aluminium rod with Young’s modulusY=7.0 ×1010 N m-2undergoes elastic strain of0.04%. The energy per unit volume stored in the rod inSIunit

Options:

Answer:
C
Solution:

The data given is 

Y=7×1010 N m-2 andll=0.04100

Young's modulus is given by the ratio of stress and strain,

Y=FAll=FlAl

The energy stored is given as 

E=YA2ll2E=YA2ll2×l   ...(i)

The energy per unit volume can be written from equation (i)

EV=Y2×ll2   ...(ii)

Substituting the values in equation (ii)

EV=12×7×1010×0.04×0.04104=56×102

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous
2mℹ️ Source: PYQ_2023

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