The average depth of the Indian ocean is about 3000 m . The fractional compression, ∆ V V of water at the bottom of the ocean ( given that the bulk modulus of the water = 2 . 2 × 10 9 N m - 2 and g = 10 ms - 2 )

∆ V V = P B ∆ V V = ρgh B = 1000 × 10 × 3000 2 . 2 × 10 9 ⇒ ∆ V V = 0 . 0136 = 1 . 36 %

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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minPYQ_2020

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The average depth of the Indian ocean is about $3000 m$ . The fractional compression, $\frac{∆ V}{V}$ of water at the bottom of the ocean ( given that the bulk modulus of the water = $2.2 \times 10^{9} N m^{- 2}$ and $g = 10 {ms}^{- 2}$ )

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Solution:

$\frac{∆ V}{V} = \frac{P}{B}$

$\frac{∆ V}{V} = \frac{ρgh}{B} = \frac{1000 \times 10 \times 3000}{2.2 \times 10^{9}}$

$\Rightarrow \frac{∆ V}{V} = 0.0136 = 1.36 %$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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