A negligible-mass rod ( A = 2 × 1 0 − 6 m 2 ) is 0.5 m long at 20 0 ∘ C . It is cooled to 0 ∘ C but held at this length by a hanging mass. Y = 1 0 11 Pa and α = 1 0 − 5 K − 1 . Mass is:

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A negligible-mass rod ( $A = 2 \times 1 0^{- 6} m^{2}$ ) is $0.5 m$ long at $20 0^{\circ} C$ . It is cooled to $0^{\circ} C$ but held at this length by a hanging mass. $Y = 1 0^{11} Pa$ and $α = 1 0^{- 5} K^{- 1}$ . Mass is:

Options:

Answer:

Solution:

$m g = Y A α Δ T = 400 N$ .

With $g = 10$ , $m = 40 kg$ .

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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