Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

The amount of work done in increasing the length of a $1 m$ long wire through $1 cm$ when the Young's modulus is $8 \times 1 0^{8} N/ m^{2}$ will be :

Options:

Answer:

Solution:

Strain $= \frac{0.01}{1} = 1 0^{- 2}$

$W = \frac{1}{2} Y (strain)^{2} \times Volume$

$W = \frac{1}{2} \times 8 \times 1 0^{8} \times 1 0^{- 4} \times V = 4 \times 1 0^{4} V$ (joule, $V$ in $m^{3}$ )

The cross-sectional area is not given, so $V$ is unknown. The work cannot be found, so the data is insufficient.

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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