Physics - Elasticity Question with Solution | TestHub

Given, mass of girl (m) = 50 kg

Diameter of circular heel (2r) = 1.0 cm

Radius (r) = 0.5 cm

= 5 × 10^-3m

Area of the circular heel (A) = πr²

= 3.14 × (5 × 10^-3)²m²

$= 78.50 \times {10}^{-6} {\mathrm{m}}^2$

The pressure exerted on the horizontal floor

$\text{p}=\frac{\text{F}}{\text{A}}=\frac{\text{mg}}{\text{A}}$

$=\frac{\text{50}\times \text{9.8}}{\text{78.50}\times {\text{10}}^{-6}}$

$= 6.24 \times {10}^6 \mathrm{Pa}$