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PhysicsElasticityMiscellaneousMedium2 minPYQ_2020

PhysicsMediumsingle choice

Speed of a transverse wave on a straight wire (mass $6.0 g,$ length $60 c m$ and area of cross-section $1.0 m m^{2}$ is $90 {m s}^{- 1}$ . If the Young's modulus of wire is $16 \times 10^{11} N m^{- 2}$ , the extension of wire over its natural length is:

Options:

Answer:

Solution:

$v = \sqrt{\frac{T}{μ}}$
$\Rightarrow T = μ v^{2}$
$\Rightarrow \frac{μ v^{2}}{A} = Y \frac{∆ l}{l}$
$\Rightarrow ∆ l = \frac{μ v^{2} l}{A Y}$
After substituting value of $μ, v, l, A$ and $Y$ we get
$∆ l = 0.3 m m$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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