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PhysicsElasticityMiscellaneousEasy2 minPYQ_2023
PhysicsEasynumerical

A metal block of mass m is suspended from a rigid support through a metal wire of diameter 14 mm. The tensile stress developed in the wire under equilibrium state is 7×105 N m2. The value of mass m is ______ kg.

(Take g=9.8 m s-2 and π=227)

Answer:
11.00
Solution:

The data given is

 T=7×105 N m-2r=7×10-3 m

Using the equation

 mgA=Tmg=TAmg=Tπr2

mg=7×105×227×72×10-6

mg=49×2210

m=49×2298=11 kg

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous
2mℹ️ Source: PYQ_2023

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