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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 min

PhysicsMediumsingle choice

A thin steel ring of inner radius r and cross-sectional area A is fitted on to a wooden disc of radius $R (R > r)$ . If Young's modulus be Y, then the tension in the steel ring is

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Solution:

$Strain = \frac{Δ l}{l} = (\frac{2 π R - 2 π r}{2 π r}) Strain = (\frac{R - r}{r}) Y = \frac{R / A}{\frac{Δ l}{T}}, Y \frac{Δ l}{l} A = F F = A Y (\frac{R - r}{r})$

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Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2m

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