Two billiard balls of mass 0 . 05 kg each moving in opposite directions with 10 ms - 1 collide and rebound with the same speed. If the time duration of contact is t = 0 . 005 s , then what is the forc

Question

Two billiard balls of mass 0 . 05 kg each moving in opposite directions with 10 ms - 1 collide and rebound with the same speed. If the time duration of contact is t = 0 . 005 s , then what is the force exerted on the ball due to each other?

TestHub · Accepted Answer

After collision, the balls change their directions of motion without changing the magnitudes of their velocity.
Change in momentum of any one ball
$|Δ \vec{p}| = 2 \times 0.05 \times 10$
$\Rightarrow |Δ \vec{p}| = 1 kg m s^{- 1}$
The force exerted on the ball is $|{\vec{F}}_{av}| = \frac{|Δ \vec{p}|}{Δ t} = \frac{1}{0.005}$
$F_{av} = 200 N$

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