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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium3 minQB

PhysicsMediumsingle choice

A circus acrobat of mass M leaps straight up with initial velocity $V_{0}$ from a trampoline. As he rises up, he takes a trained monkey of mass m hanging from a branch at a height h above the trampoline. What is the maximum height attained by the pair (from the branch)?

Options:

Answer:

Solution:

At the branch: $v^{2} = V_{0}^{2} - 2 g h$ . Picking up the monkey conserves momentum: $v^{'} = \frac{M v}{M + m}$ . Extra height $= \frac{v ^{'2}}{2 g} = (\frac{M}{M + m})^{2} (\frac{V _{0}^{2}}{2 g} - h)$ . Answer: (B)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

⏱ 3mℹ️ Source: QB

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