Two objects of masses 200 g and 500 g possess velocities 10 i ^ m/s and ( 3 i ^ + 5 j ^ ) m/s respectively. The velocity of their centre of mass in m/s is :-

( v c m ) x = 700 200 × 10 + 500 × 3 = 700 3500 = 5 . ( v c m ) y = 700 200 × 0 + 500 × 5 = 7 25 . Velocity of COM = ( 5 i ^ + 7 25 j ^ ) m/s . Hence (C).

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PhysicsCenter of MassMotion of centre of massMedium2 minQB

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Two objects of masses 200 g and 500 g possess velocities $10 \hat{i} m/s$ and $(3 \hat{i} + 5 \hat{j}) m/s$ respectively. The velocity of their centre of mass in m/s is :-

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Solution:

$(v_{c m})_{x} = \frac{200 \times 10 + 500 \times 3}{700} = \frac{3500}{700} = 5$ .

$(v_{c m})_{y} = \frac{200 \times 0 + 500 \times 5}{700} = \frac{25}{7}$ .

Velocity of COM $= (5 \hat{i} + \frac{25}{7} \hat{j}) m/s$ . Hence (C).

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Motion of centre of mass

⏱ 2mℹ️ Source: QB

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