Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMotion of centre of massMedium2 minQB

PhysicsMediuminteger

In the given arrangement, both blocks are of same mass 2 kg . Initially spring is compressed by 10 cm . Spring constant is $200 N / m$ . Find the ratio of magnitude of relative acceleration of the two blocks and acceleration of centre of mass of two blocks immediately after release ? (consider spring to be massless and incline plane to be frictionless)

Answer:

Solution:

$a_{A} = \frac{2 g s i n 3 0 ^{\circ} + kx}{2} = 15 m / s^{2}$ downward, $a_{B} = \frac{kx - 2 g s i n 3 0 ^{\circ}}{2} = 5 m / s^{2}$ upwards

$a_{rel} = 20 m / s^{2} a_{cm} = \frac{[ 15 m / s ^{2} - 5 m / s ^{2} ] M}{2 M} = 5 m / s^{2}$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Motion of centre of mass

⏱ 2mℹ️ Source: QB

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