In a scattering experiment, a particle of mass $3 m$ collides with another particle of mass $m$ , which is initially at rest. Assuming the collision to be perfectly elastic, the maximum angular deviation $θ$ of the heavier particle, as shown in the figure, in radians is :-

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TestHub · Accepted Answer

3 m u = 3 m v 1 ​ cos θ + m v 2 ​ cos α 0 = 3 m v 1 ​ sin θ − m v 2 ​ sin α 3 u 2 = 3 v 1 2 ​ + v 2 2 ​ 12 v 1 2 ​ − 18 u v 1 ​ cos θ + 6 u 2 = 0 cos 2 θ ≥ 9 8 ​ ⇒ tan θ ma x ​ = 8 ​ 1 ​ Hence option C.

Physics - Center of Mass Question with Solution | TestHub

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