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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

A wrecking ball attached to the end of a long, light chain is released from rest, from a height H = 5 meters off the ground, as shown in the figure. At the lowest point of its swing, it collides with a piece of modern sculpture. Since the sculpture is made of wet clay, it sticks to the wrecking ball. The wrecking ball has mass 200 kg. The sculpture has mass 100 kg.

Maximum height reached by system (ball + sculpture) on the right side is

Options:

Answer:

Solution:

$Veloicty of (ball + sculpture) system = \frac{m _{b} 2 g H}{m _{b} + m _{s}} { momentum conservation} ∴ Maximum height reached = \frac{K E}{( m _{b} + m _{s} ) g} = \frac{\frac{1}{2} ( m _{b} + m _{s} ) ( \frac{m _{b} 2 g H}{m _{b} + m _{s}} ) ^{2}}{( m _{b} + m _{s} ) g} = \frac{20}{9} m$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: QB

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