Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCalculate of COMEasy2 minQB

PhysicsEasysingle choice

Centre of mass of 3 particles of $10 kg, 20 kg$ and 30 kg is at $(0, 0, 0)$ . Where should a particle of 40kg be placed so that the combined centre of mas will be at $(3, 3, 3)$ ?

Options:

Answer:

Solution:

In the first case,

$x_{c m} = \frac{10 x _{1} + 20 x _{2} + 30 x _{3}}{60} = 0$

or $10 x_{1} + 20 x_{2} + 30 x_{3} = 0$

In the second case,

$x_{cm} = \frac{10 x _{1} + 20 x _{2} + 30 x _{3} + 40 x _{4}}{100} = 3$

or $\frac{40 x _{4}}{100} = 3 \Rightarrow x_{4} = 7.5$ units

Similarly $y_{4} = z_{4} = 7.5$ units

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Calculate of COM

⏱ 2mℹ️ Source: QB

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