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Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICalculation of DSEasy2 minPYQ_2022
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The standard entropy change for the reaction

4Fes+3O2g2Fe2O3s is -550 J K-1 at 298 K

[Given : The standard enthalpy change for the reaction is -165 kJ mol-1]. The temperature in K at which the reaction attains equilibrium is (Nearest Integer)

Answer:
300
Solution:

4Fes+3O2g3Fe2O3s  ΔSr=-550 J/K

ΔSr=-165 kJ/mole

At equilibrium ΔG=0

T=ΔHΔS at equilibrium

=-165×103-550=300 K

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
2mℹ️ Source: PYQ_2022

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