Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIFree Energy and EquilibriumHard2 minPYQ_2021
ChemistryHardnumerical
Passage / Comprehension

For the reaction, , the plot of versus is given below (in solid line), where is the pressure (in bar) of the gas at temperature and bar.

(Given, , where the equilibrium constant, and the gas constant, )

The value of standard enthalpy, Ho (in kJ mol-1) for the given reaction is ___.

Answer:
166.28
Solution:

Slopgthe Given graph

d lnpzpϕd 104T=7+31210=2

d lnpzpϕd1T2×104=ΔHoR

ΔHo=2×104×R

=2×8.314×10 kJ/mol

=166.28

Stream:JEE_ADVSubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
2mℹ️ Source: PYQ_2021

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