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Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIFree Energy and EquilibriumHard2 minPYQ_2021
ChemistryHardnumerical

For the reaction AgBg at 495 KΔrG°=-9.478 kJ mol-1

If we start the reaction in a closed container at 495 K with 22 millimoles of A, the amount of B is the equilibrium mixture is ________ millimoles. (Round off to the Nearest Integer).

R=8.314 J mol-1 K-1;n10=2.303

Answer:
20.00
Solution:

ΔG°=-RTℓnKeq

Given ΔG°=-9.478 KJ/mole

T=495 K  R=8.314 J mol-1

So -9.478×103=-495×8.314×nKeq

nKeq=2.303

=n10

So Keq=10

Now AgBgt=0220t=022-xx

Keq=BC=x22-x=10

or x=20

So millimoles of B=20

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
2mℹ️ Source: PYQ_2021

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