Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIFree Energy and EquilibriumMedium2 minPYQ_2016
ChemistryMediummatching list

For the reaction,

Ag+Bg→Cg+Dg, ∆Hoand∆Soare, respectively,-29.8 kJ mol-1and-0.100 kJ K-1 mol-1at 298 K. The equilibrium constant for the reaction at 298 k is:

Options:

Answer:
C
Solution:

∆G°= ∆H°-T∆S°

∆G°=-29.8 kJmol-1+0.1×298 kJmol-1=0

∆G= ∆G°+RTlnQ  at Equilibrium ∆G=0 & Q=k

∆G°=-RTln(K)

if ln(K)=0,  K=e0

∴K=1

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
⏱ 2mℹ️ Source: PYQ_2016

Doubts & Discussion

Loading discussions...